Friday, January 20, 2012

Write a C program to print the following pattern:


1.      Write a C program to print the following pattern:
2.  *
3.        *  *
4.     *  *  *
5.  *  *  *  *
6.      Write a C program to print the following pattern:
7.  *                   *
8.  * * *           * * *
9.  * * * * *   * * * * *
10.* * * * * * * * * * *
11.  Write a C program to print the following pattern:
12.*                         *
13.   *                   *
14.*     *             *     *
15.   *     *       *     *
16.*     *      *      *     *
17.   *     *       *     *
18.*     *             *     *
19.   *                   *
20.*                         *
21.  Write a C program to print the following pattern:
22.*   *   *   *   *
23.  *   *   *   *
24.    *   *   *
25.      *   *
26.        *
27.      *   *
28.    *   *   *
29.  *   *   *   *
30.*   *   *   *   *
31.  Write a C program to print the following pattern:
32.*
33.        * * *
34.      * * * * *
35.    * * * * * * *
36.  * * * * * * * * *
37.    * * * * * * *
38.      * * * * *
39.        * * *
40.          *
41.        * * *
42.      * * * * *
43.  Write a C program to print the following pattern:
44.*
45.       * *
46.         * * *
47.           * * * *
48.         * * *
49.       * *
50.     *
51.  Write a C program to print the following pattern:
52.* * * * * * * * *
53.* * * *   * * * *
54.* * *       * * *
55.* *           * *
56.*               *
57.* *           * *
58.* * *       * * *
59.* * * *   * * * *
60.* * * * * * * * *
61.  Write a C program to print the following pattern:
62.* * * * * * * * * * * * * * * * *
63.  * * * * * * *   * * * * * * *
64.    * * * * *       * * * * *
65.      * * *           * * *
66.        * * * * * * * * *
67.          * * * * * * *
68.            * * * * *
69.              * * *
70.                *
71.  Write a C program to print the following pattern:
72.*
73.    * * *
74.  * * * * *
75.* * * * * * *
76.*           *
77.* *       * *
78.* * *   * * *
79.* * * * * * *
80.* * *   * * *
81.* *       * *
82.*           *
83.* * * * * * *
84.  * * * * *
85.    * * *
86.      *
87.  Write a C program to print the following pattern:
88.* * * * * * * * * * * * * * * * * * * * * * * * *
89.  *           *   *           *   *           *
90.    *       *       *       *       *       *
91.      *   *           *   *           *   *
92.        *               *               *
93.      *   *           *   *           *   *
94.    *       *       *       *       *       *
95.  *           *   *           *   *           *
96.* * * * * * * * * * * * * * * * * * * * * * * * *
  1. Write a C program to print the following pattern:
*
      *  *
   *  *  *
*  *  *  *
Program:
/* This is a simple mirror-image of a right angle triangle */

#include
int main() {
 char prnt = '*';
 int i, j, nos = 4, s;
 for (i = 1; i <= 5; i++) {
for (s = nos; s >= 1; s--) {  // Spacing factor
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  printf("\n");
  --nos;   // Controls the spacing factor
 }
 return 0;
}
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  1. Write C program to print the following pattern:
3.  *                   *
4.  * * *           * * *
5.  * * * * *   * * * * *
* * * * * * * * * * *
Program:
#include
int main() {
 char prnt = '*';
 int i, j, k, s, c = 1, nos = 9;
 for (i = 1; c <= 4; i++) {
     // As we want to print the columns in odd sequence viz. 1,3,5,.etc
  if ((i % 2) != 0) {
   for (j = 1; j <= i; j++) {
 printf("%2c", prnt);
}
for (s = nos; s >= 1; s--) { //The spacing factor
    if (c == 4 && s == 1) {
     break;
    }
    printf("  ");
   }
   for (k = 1; k <= i; k++) {
    if (c == 4 && k == 5) {
     break;
    }
    printf("%2c", prnt);
   }
   printf("\n");
   nos = nos - 4;  // controls the spacing factor
   ++c;
  }
 }
 return 0;
}
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  1. Write C program to print the following pattern:
7.  *                         *
8.     *                   *
9.  *     *             *     *
10.   *     *       *     *
11.*     *      *      *     *
12.   *     *       *     *
13.*     *             *     *
14.   *                   *
*                         *
Program:
#include
int main() {
 char prnt = '*';
 int i, j, k, s, p, r, nos = 7;

 for (i = 1; i <= 5; i++) {
  for (j = 1; j <= i; j++) {
 if ((i % 2) != 0 && (j % 2) != 0) {
printf("%3c", prnt);
}
else if ((i % 2) == 0 && (j % 2) == 0) {
printf("%3c", prnt);
}
else {
printf("   ");
}
}
for (s = nos; s >= 1; s--) {  // for the spacing factor
   printf("   ");
  }
  for (k = 1; k <= i; k++) { //Joining seperate figures
if (i == 5 && k == 1) {
 continue;
}
if ((k % 2) != 0) {
printf("%3c", prnt);
}
else {
printf("   ");
}
}
printf("\n");
nos = nos - 2;   // space control
}  nos = 1;  // remaining half..
for (p = 4; p >= 1; p--) {
  for (r = 1; r <= p; r++) {
if ((p % 2) != 0 && (r % 2) != 0) {
printf("%3c", prnt);
}
else if ((p % 2) == 0 && (r % 2) == 0) {
printf("%3c", prnt);
}
else {
printf("   ");
}
}
for (s = nos; s >= 1; s--) {
   printf("   ");
  }
  for (k = 1; k <= p; k++) {
   if ((k % 2) != 0) {
    printf("%3c", prnt);
   }
else {
    printf("   ");
   }
  }
  nos = nos + 2;  // space control
  printf("\n");
 }
 return 0;
}
Download Code Explanation: This can be seen as an inverted diamond composed of stars. It can be noted that the composition of this figure follows sequential pattern of consecutive stars and spaces. In case of odd row number, the odd column positions will be filled up with ‘*’, else a space will be spaced and vice-versa in case of even numbered row. In order to achieve this we will construct four different right angle triagles aligned as per the requirement.
  1. Write a C program to print the following pattern:
16.*   *   *   *   *
17.  *   *   *   *
18.    *   *   *
19.      *   *
20.        *
21.      *   *
22.    *   *   *
23.  *   *   *   *
*   *   *   *   *
Program:
#include
int main() {
 char prnt = '*';
 int i, j, s, nos = 0;
 for (i = 9; i >= 1; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
   } else {
    printf("  ");
   }
  }
  printf("\n");
  nos++;
 }
 nos = 3;
 for (i = 3; i <= 9; (i = i + 2)) {
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {

   if ((i % 2) != 0 && (j % 2) != 0) {
    printf("%2c", prnt);
   } else {
    printf("  ");
   }
  }
  nos--;
  printf("\n");
 }
 return 0;
}
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  1. Write a C program to print the following pattern:
25.*
26.        * * *
27.      * * * * *
28.    * * * * * * *
29.  * * * * * * * * *
30.    * * * * * * *
31.      * * * * *
32.        * * *
33.          *
34.        * * *
      * * * * *
Program:
#include
int main() {
 char prnt = '*';
 int i, j, k, s, nos = 4;
 for (i = 1; i <= 5; i++) {
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  for (k = 1; k <= (i - 1); k++) {
if (i == 1) {     continue;
}
printf("%2c", prnt);
}
 printf("\n");   nos--;
}
 nos = 1;
for (i = 4; i >= 1; i--) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  for (k = 1; k <= (i - 1); k++) {
   printf("%2c", prnt);
  }
  nos++;
  printf("\n");
 }
 nos = 3;
 for (i = 2; i <= 5; i++) {
if ((i % 2) != 0) {
for (s = nos; s >= 1; s--) {
    printf("  ");
   }
   for (j = 1; j <= i; j++) {
    printf("%2c", prnt);
   }
  }
  if ((i % 2) != 0) {
   printf("\n");
   nos--;
  }
 }
 return 0;
}
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  1. Write a C program to print the following pattern:
36.*
37.       * *
38.         * * *
39.           * * * *
40.         * * *
41.       * *
     *
Program:
/*
    This can be seen as two right angle triangles sharing the same base
    which is modified by adding few extra shifting spaces
*/
#include
// This function controls the inner loop and the spacing
// factor guided by the outer loop index and the spacing index.
int triangle(int nos, int i) {
 char prnt = '*';
 int s, j;
 for (s = nos; s >= 1; s--) {    // Spacing factor
  printf("  ");
 }
 for (j = 1; j <= i; j++) {      //The inner loop
  printf("%2c", prnt);
 }
 return 0;
}

int main() {
 int i, nos = 5;
 //draws the upper triangle
 for (i = 1; i <= 4; i++) {
 triangle(nos, i);    //Inner loop construction
 nos++;              // Increments the spacing factor
 printf("\n");  }
nos = 7;  //Draws the lower triangle skipping its base.
for (i = 3; i >= 1; i--) {
  int j = 1;
  triangle(nos, i);  // Inner loop construction
  nos = nos - j;     // Spacing factor
  printf("\n");
 }
 return 0;
}
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  1. Write a C program to print the following pattern:
43.* * * * * * * * *
44.* * * *   * * * *
45.* * *       * * *
46.* *           * *
47.*               *
48.* *           * *
49.* * *       * * *
50.* * * *   * * * *
* * * * * * * * *
Program:
#include

int main() {
 char prnt = '*';
 int i, j, k, s, nos = -1;
 for (i = 5; i >= 1; i--) {
  for (j = 1; j <= i; j++) {
 printf("%2c", prnt);
}
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (k = 1; k <= i; k++) {
   if (i == 5 && k == 5) {
    continue;
   }
   printf("%2c", prnt);
  }
  nos = nos + 2;
  printf("\n");
 }
 nos = 5;
 for (i = 2; i <= 5; i++) {
  for (j = 1; j <= i; j++) {
 printf("%2c", prnt);
}
for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (k = 1; k <= i; k++) {
   if (i == 5 && k == 5) {
    break;
   }
   printf("%2c", prnt);
  }
  nos = nos - 2;
  printf("\n");
 }
 return 0;
}
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  1. Write a C program to print the following pattern:
52.* * * * * * * * * * * * * * * * *
53.  * * * * * * *   * * * * * * *
54.    * * * * *       * * * * *
55.      * * *           * * *
56.        * * * * * * * * *
57.          * * * * * * *
58.            * * * * *
59.              * * *
                *
Program:
#include
int main() {
 char prnt = '*';
 int i, j, k, s, sp, nos = 0, nosp = -1;
 for (i = 9; i >= 3; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
printf("%2c", prnt);
}
for (sp = nosp; sp >= 1; sp--) {
   printf("  ");
  }
  for (k = 1; k <= i; k++) {
 if (i == 9 && k == 1) {
continue;
}
printf("%2c", prnt);
}
nos++;
nosp = nosp + 2;
printf("\n");
}
nos = 4;
for (i = 9; i >= 1; (i = i - 2)) {
  for (s = nos; s >= 1; s--) {
   printf("  ");
  }
  for (j = 1; j <= i; j++) {
   printf("%2c", prnt);
  }
  nos++;
  printf("\n");
 }

 return 0;
}
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  1. Write a C program to print the following pattern:
61.*
62.    * * *
63.  * * * * *
64.* * * * * * *
65.*           *
66.* *       * *
67.* * *   * * *
68.* * * * * * *
69.* * *   * * *
70.* *       * *
71.*           *
72.* * * * * * *
73.  * * * * *
74.    * * *
      *
Program:
#include
/*
 * nos = Num. of spaces required in the triangle.
 * i   = Counter for the num. of charcters to print in each row
 * skip= A flag for checking whether to
 *       skip a character in a row.
 *
 */
int triangle(int nos, int i, int skip) {
 char prnt = '*';
 int s, j;
 for (s = nos; s >= 1; s--) {
  printf("  ");
 }
 for (j = 1; j <= i; j++) {
  if (skip != 0) {
   if (i == 4 && j == 1) {
    continue;
   }
  }
  printf("%2c", prnt);
 }
 return 0;
}

int main() {
 int i, nos = 4;
 for (i = 1; i <= 7; (i = i + 2)) {
  triangle(nos, i, 0);
  nos--;
  printf("\n");
 }
 nos = 5;
 for (i = 1; i <= 4; i++) {
triangle(1, i, 0); //one space needed in each case of the formation
triangle(nos, i, 1); //skip printing one star in the last row.
nos = nos - 2;
printf("\n");
}
nos = 1;
for (i = 3; i >= 1; i--) {
  triangle(1, i, 0);
  triangle(nos, i, 0);
  nos = nos + 2;
  printf("\n");
 }
 nos = 1;
 for (i = 7; i >= 1; (i = i - 2)) {
  triangle(nos, i, 0);
  nos++;
  printf("\n");
 }
 return 0;
}
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  1. Write a C program to print the following pattern:
76.* * * * * * * * * * * * * * * * * * * * * * * * *
77.  *           *   *           *   *           *
78.    *       *       *       *       *       *
79.      *   *           *   *           *   *
80.        *               *               *
81.      *   *           *   *           *   *
82.    *       *       *       *       *       *
83.  *           *   *           *   *           *
* * * * * * * * * * * * * * * * * * * * * * * * *
Program:
#include

/*
 * nos = Num. of spaces required in the triangle.
 * i   = Counter for the num. of characters to print in each row
 * skip= A flag for check whether to
 *       skip a character in a row.
 *
 */

int triangle(int nos, int i, int skip) {
 char prnt = '*';
 int s, j;
 for (s = nos; s >= 1; s--) {
  printf("  ");
 }
 for (j = 1; j <= i; j++) {
 if (skip != 0) {
 if (i == 9 && j == 1) {
   continue;
 }
 }
if (i == 1 || i == 9) {
 printf("%2c", prnt);
}
else if (j == 1 || j == i) {
 printf("%2c", prnt);
 } else {
 printf("  ");
}  }
return 0; }
int main() {
int i, nos = 0, nosp = -1, nbsp = -1;
for (i = 9; i >= 1; (i = i - 2)) {
  triangle(nos, i, 0);
  triangle(nosp, i, 1);
  triangle(nbsp, i, 1);
  printf("\n");
  nos++;
  nosp = nosp + 2;
  nbsp = nbsp + 2;
 }
 nos = 3, nosp = 5, nbsp = 5;
 for (i = 3; i <= 9; (i = i + 2)) {
  triangle(nos, i, 0);
  triangle(nosp, i, 1);
  triangle(nbsp, i, 1);
  printf("\n");
  nos--;
  nosp = nosp - 2;
  nbsp = nbsp - 2;
 }
 return 0;
}

Read more: http://cmagical.blogspot.com/2010/01/10-challenging-star-pattern-programs-in.html#ixzz1jhAznHcm
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